4x^2-60x+80=0

Solution for 4x^2-60x+80=0 equation:

4x^2-60x+80=0

a = 4; b = -60; c = +80;
Δ = b2-4ac
Δ = -602-4·4·80
Δ = 2320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2320}=\sqrt{16*145}=\sqrt{16}*\sqrt{145}=4\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{145}}{2*4}=\frac{60-4\sqrt{145}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{145}}{2*4}=\frac{60+4\sqrt{145}}{8}
$